[cairo] How to get extents of transformed graphics
Andreas Falkenhahn
andreas at falkenhahn.com
Thu Sep 8 17:24:03 UTC 2022
I've tried this:
width = fabs(x2 - floor(x1));
height = fabs(y2 - floor(y1));
width = ceil(width * 4.6);
height = ceil(height * 4.6);
Still cuts off a line of the "C" shape. I've also tried this:
width = fabs(ceil(x2) - floor(x1));
height = fabs(ceil(y2) - floor(y1));
width = ceil(width * 4.6);
height = ceil(height * 4.6);
No success either. A line is cut off.
Any more ideas? You can find my test program below...
On 08.09.2022 at 19:03 Behdad Esfahbod wrote:
> Try flooring x1,y1 before subtracting them from x2,y2 for computing the size of your surface.
> behdad
> http://behdad.org/
> On Thu, Sep 8, 2022 at 10:21 AM Andreas Falkenhahn <andreas at falkenhahn.com> wrote:
> Is there really nobody who knows how to solve this? There surely
> must be a way to find out the *exact* extents of transformed
> graphics? The idea is to find out the exact dimensions in order to
> allocate a Cairo surface that *exactly* matches the size of the path.
>
> On 28.08.2022 at 21:47 Andreas Falkenhahn wrote:
>
>> Hi,
>
>> is there any way to get the *exact* extents of transformed
>> graphics? AFAICS, cairo_fill_extents() is in user coordinates, i.e.
>> it doesn't take any transformation settings into account. So I've
>> tried to apply the transformation manually to what I get from
>> cairo_fill_extents() but I don't seem to get it 100% right. It looks
>> like one row is missing at the bottom.
>
>> This is what I've tried:
>
>> cairo_t *cr;
>> cairo_surface_t *surface;
>> cairo_matrix_t cm;
>> int k;
>> double tx = 0, ty = 0;
>> double x1, y1, x2, y2;
>>
>> surface = cairo_image_surface_create(CAIRO_FORMAT_A8, 1000, 1000);
>> cr = cairo_create(surface);
>
>> for(k = 0; k < 2; k++) {
>>
>> cairo_new_path(cr);
>> cairo_move_to(cr, tx, ty);
>> cairo_set_font_size(cr, 100);
>> cairo_text_path(cr, "C");
>>
>> if(!k) {
>>
>> double width, height;
>>
>> cairo_fill_extents(cr, &x1, &y1, &x2, &y2);
>>
>> tx = -x1;
>> ty = -y1;
>>
>> width = fabs(x2 - x1);
>> height = fabs(y2 - y1);
>
>> width = ceil(width * 4.6);
>> height = ceil(height * 4.6);
>>
>> cairo_destroy(cr);
>> cairo_surface_destroy(surface);
>>
>> surface =
>> cairo_image_surface_create(CAIRO_FORMAT_A8, width, height);
>> cr = cairo_create(surface);
>>
>> cairo_matrix_init(&cm, 4.6, 0, 0, 4.6, 0, 0);
>> cairo_set_matrix(cr, &cm);
>> }
>> }
>>
>> cairo_fill(cr);
>
>> cairo_surface_flush(surface);
>> cairo_surface_write_to_png(surface, "tmp.png");
>>
>> cairo_destroy(cr);
>> cairo_surface_destroy(surface);
>
>> I'm attaching the resulting image. As you can see, there's at least
>> one row of the "C" shape missing at the bottom of the image.
>
>> Any ideas how to get this right? Is this some sort of floating
>> point inaccuracy and should I just add 1 to width/height to solve
>> this or am I doing something wrong here and there is a better way?
>
>
>
> --
> Best regards,
> Andreas Falkenhahn mailto:andreas at falkenhahn.com
>
>
--
Best regards,
Andreas Falkenhahn mailto:andreas at falkenhahn.com
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